A platform for research: civil engineering, architecture and urbanism
The invention discloses a barium titanate-based ceramic material with high energy storage density and high energy storage efficiency as well as a preparation method and application of the barium titanate-based ceramic material. The chemical composition of the ceramic material is (1-x) (Ba0. 91Ca0. 09) (Ti0. 86Zr0. 14) O3.xBi (Mg2/3Nb1/3) O3, x represents the molar fraction of Bi (Mg2/3Nb1/3) O3, and x is larger than or equal to 0.025 and smaller than or equal to 0.15. According to the invention, Ba < 2 + > and Ca < 2 + > at (Ba0. 91Ca0. 09) (Ti < 0.86 > Zr < 0.14 >) O3A site are substituted by Bi < 3 + >, Ti < 4 + > and Zr < 4 + > at (Ba0. 91Ca0. 09) (Ti < 0.86 > Zr < 0.14 >) O3B site are substituted by Mg < 2 + > and Nb < 5 + >, and then a compact and uniform sample is synthesized by adopting a standard solid-phase sintering method. The barium titanate-based ceramic material prepared in the invention has excellent energy storage performance, the recoverable energy storage density calculated based on a ferroelectric hysteresis loop is as high as 8.68 J/cm < 3 >, the energy storage efficiency is as high as 92.8%, and the preparation method is simple, low in cost, environment-friendly, stable in performance and suitable for large-scale production.
本发明公开了一种兼具高储能密度和高储能效率的钛酸钡基陶瓷材料及其制备方法和应用。本发明的陶瓷材料的化学组成为(1‑x)(Ba0.91Ca0.09)(Ti0.86Zr0.14)O3﹒xBi(Mg2/3Nb1/3)O3,其中x表示Bi(Mg2/3Nb1/3)O3的摩尔分数,且0.025≤x≤0.15。本发明采用用Bi3+取代(Ba0.91Ca0.09)(Ti0.86Zr0.14)O3A位的Ba2+和Ca2+,用Mg2+和Nb5+取代(Ba0.91Ca0.09)(Ti0.86Zr0.14)O3B位的Ti4+和Zr4+,然后采用标准固相烧结法合成致密均匀的样品。本发明中制备的钛酸钡基陶瓷材料的储能性能优异,基于电滞回线计算的可恢复储能密度高达8.68J/cm3,同时储能效率高达92.8%,而且制备方法简单,成本低廉,对环境友好,性能稳定,可以大规模生产。
The invention discloses a barium titanate-based ceramic material with high energy storage density and high energy storage efficiency as well as a preparation method and application of the barium titanate-based ceramic material. The chemical composition of the ceramic material is (1-x) (Ba0. 91Ca0. 09) (Ti0. 86Zr0. 14) O3.xBi (Mg2/3Nb1/3) O3, x represents the molar fraction of Bi (Mg2/3Nb1/3) O3, and x is larger than or equal to 0.025 and smaller than or equal to 0.15. According to the invention, Ba < 2 + > and Ca < 2 + > at (Ba0. 91Ca0. 09) (Ti < 0.86 > Zr < 0.14 >) O3A site are substituted by Bi < 3 + >, Ti < 4 + > and Zr < 4 + > at (Ba0. 91Ca0. 09) (Ti < 0.86 > Zr < 0.14 >) O3B site are substituted by Mg < 2 + > and Nb < 5 + >, and then a compact and uniform sample is synthesized by adopting a standard solid-phase sintering method. The barium titanate-based ceramic material prepared in the invention has excellent energy storage performance, the recoverable energy storage density calculated based on a ferroelectric hysteresis loop is as high as 8.68 J/cm < 3 >, the energy storage efficiency is as high as 92.8%, and the preparation method is simple, low in cost, environment-friendly, stable in performance and suitable for large-scale production.
本发明公开了一种兼具高储能密度和高储能效率的钛酸钡基陶瓷材料及其制备方法和应用。本发明的陶瓷材料的化学组成为(1‑x)(Ba0.91Ca0.09)(Ti0.86Zr0.14)O3﹒xBi(Mg2/3Nb1/3)O3,其中x表示Bi(Mg2/3Nb1/3)O3的摩尔分数,且0.025≤x≤0.15。本发明采用用Bi3+取代(Ba0.91Ca0.09)(Ti0.86Zr0.14)O3A位的Ba2+和Ca2+,用Mg2+和Nb5+取代(Ba0.91Ca0.09)(Ti0.86Zr0.14)O3B位的Ti4+和Zr4+,然后采用标准固相烧结法合成致密均匀的样品。本发明中制备的钛酸钡基陶瓷材料的储能性能优异,基于电滞回线计算的可恢复储能密度高达8.68J/cm3,同时储能效率高达92.8%,而且制备方法简单,成本低廉,对环境友好,性能稳定,可以大规模生产。
Barium titanate-based ceramic material with high energy storage density and high energy storage efficiency as well as preparation method and application of barium titanate-based ceramic material
一种兼具高储能密度和高储能效率的钛酸钡基陶瓷材料及其制备方法和用途
2024-06-14
Patent
Electronic Resource
Chinese
IPC:
C04B
Kalk
,
LIME
European Patent Office | 2024
|Barium titanate-based energy storage ceramic material and preparation method thereof
European Patent Office | 2022
|European Patent Office | 2024
|Barium strontium titanate-based energy storage ceramic material and preparation method thereof
European Patent Office | 2024
|