A platform for research: civil engineering, architecture and urbanism
A platform for research: civil engineering, architecture and urbanism
OUTER WALL MEMBER AND BUILDING
To provide an outer wall member which can reduce a flow-in/out calorie to/from a room, and can reduce cooling/heating energy when constantly maintaining room temperature by using cooling/heating equipment irrespective of a variation of an outdoor atmospheric temperature, and a building having the outer wall member.SOLUTION: In an outer wall member 1, a heat storage layer is arranged between an outdoor heat insulation layer 3 and an indoor heat insulation layer 4, and R expressed by the following formula (3) is 0.20 or smaller. R=2(R1-0.5)2+(R2-1)2+(R3-0.55)2 (3). (In the formula (3), R1 is expressed by the following formula (1).) R1=(Tb/Kb)/(Ta/Ka+Tb/Kb)(1), where Ka is the heat conductivity of the outdoor heat insulation layer 3, Ta is a thickness of the outdoor heat insulation layer 3, Kb is the heat conductivity of the indoor heat insulation layer 4, and Tb is a thickness of the indoor heat insulation layer 4. R2 is a ratio of a latent heat amount of the heat storage layer within a temperature range from 15°C up to 40°C with respect to a latent heat amount within a temperature range from -10°C up to 60°C. R3=L5/L20 (2).SELECTED DRAWING: Figure 1
【課題】室外の気温の変動によらず、冷暖房設備により室内の温度を一定に保持させる際に、室内への流出入熱量を小さくし、冷暖房エネルギーを低減することが可能な外壁部材及び該外壁部材を備えた建築物を提供する。【解決手段】室外側断熱層３と室内側断熱層４との間に、蓄熱層を有し、下式（３）で表されるＲが０．２０以下である外壁部材１。Ｒ＝２（Ｒ１−０．５）２＋（Ｒ２−１）２＋（Ｒ３−０．５５）２（３）、（式（３）中、Ｒ１は下式（１）で表される。Ｒ１=（Ｔｂ／Ｋｂ）／（Ｔａ／Ｋａ+Ｔｂ／Ｋｂ）（１）、Ｋａは室外側断熱層３の熱伝導率であり、Ｔａは室外側断熱層３の厚みであり、Ｋｂは室内側断熱層４の熱伝導率であり、Ｔｂは室内側断熱層４の厚みである。Ｒ２は、蓄熱層の、−１０℃から６０℃の温度範囲内の潜熱量に対する、１５℃から４０℃の温度範囲内の潜熱量の比である。Ｒ３＝Ｌ５／Ｌ２０（２）【選択図】図１
OUTER WALL MEMBER AND BUILDING
To provide an outer wall member which can reduce a flow-in/out calorie to/from a room, and can reduce cooling/heating energy when constantly maintaining room temperature by using cooling/heating equipment irrespective of a variation of an outdoor atmospheric temperature, and a building having the outer wall member.SOLUTION: In an outer wall member 1, a heat storage layer is arranged between an outdoor heat insulation layer 3 and an indoor heat insulation layer 4, and R expressed by the following formula (3) is 0.20 or smaller. R=2(R1-0.5)2+(R2-1)2+(R3-0.55)2 (3). (In the formula (3), R1 is expressed by the following formula (1).) R1=(Tb/Kb)/(Ta/Ka+Tb/Kb)(1), where Ka is the heat conductivity of the outdoor heat insulation layer 3, Ta is a thickness of the outdoor heat insulation layer 3, Kb is the heat conductivity of the indoor heat insulation layer 4, and Tb is a thickness of the indoor heat insulation layer 4. R2 is a ratio of a latent heat amount of the heat storage layer within a temperature range from 15°C up to 40°C with respect to a latent heat amount within a temperature range from -10°C up to 60°C. R3=L5/L20 (2).SELECTED DRAWING: Figure 1
【課題】室外の気温の変動によらず、冷暖房設備により室内の温度を一定に保持させる際に、室内への流出入熱量を小さくし、冷暖房エネルギーを低減することが可能な外壁部材及び該外壁部材を備えた建築物を提供する。【解決手段】室外側断熱層３と室内側断熱層４との間に、蓄熱層を有し、下式（３）で表されるＲが０．２０以下である外壁部材１。Ｒ＝２（Ｒ１−０．５）２＋（Ｒ２−１）２＋（Ｒ３−０．５５）２（３）、（式（３）中、Ｒ１は下式（１）で表される。Ｒ１=（Ｔｂ／Ｋｂ）／（Ｔａ／Ｋａ+Ｔｂ／Ｋｂ）（１）、Ｋａは室外側断熱層３の熱伝導率であり、Ｔａは室外側断熱層３の厚みであり、Ｋｂは室内側断熱層４の熱伝導率であり、Ｔｂは室内側断熱層４の厚みである。Ｒ２は、蓄熱層の、−１０℃から６０℃の温度範囲内の潜熱量に対する、１５℃から４０℃の温度範囲内の潜熱量の比である。Ｒ３＝Ｌ５／Ｌ２０（２）【選択図】図１
OUTER WALL MEMBER AND BUILDING
外壁部材及び建築物
HIROTA TOMOO (author) / MATSUI HIROICHI (author)
2020-07-27
Patent
Electronic Resource
Japanese
IPC:
E04B
Allgemeine Baukonstruktionen
,
GENERAL BUILDING CONSTRUCTIONS
/
B32B
LAYERED PRODUCTS, i.e. PRODUCTS BUILT-UP OF STRATA OF FLAT OR NON-FLAT, e.g. CELLULAR OR HONEYCOMB, FORM
,
Schichtkörper, d.h. aus Ebenen oder gewölbten Schichten, z.B. mit zell- oder wabenförmiger Form, aufgebaute Erzeugnisse
/
E04F
FINISHING WORK ON BUILDINGS, e.g. STAIRS, FLOORS
,
Ausbau von Bauwerken, z.B. Treppen, Fußböden