A platform for research: civil engineering, architecture and urbanism
A platform for research: civil engineering, architecture and urbanism
ROOF MEMBER OR CEILING MEMBER, AND BUILDING
To provide a roof member or a ceiling member which can reduce a flow-in/out calorie to/from a room when constantly maintaining room temperature by cooling/heating equipment irrespective of a variation of an outdoor atmospheric temperature, and can reduce cooling/heating energy.SOLUTION: In a roof member 1 or a ceiling member, a heat storage layer 2 is arranged between an outdoor heat insulation layer 3 and an indoor heat insulation layer 4, and R expressed by the following formula (3) is 0.10 or smaller. R=2(R1-0.5)2+(R2-1)2+(R3-0.55)2 (3), and R1=(Tb/Kb)/(Ta/Ka+Tb/Kb) (1), where Ka is the heat conductivity of the outdoor heat insulation layer 3, Ta is a thickness of the outdoor heat insulation layer 3, Kb is the heat conductivity of the indoor heat insulation layer 4, and Tb is a thickness of the indoor heat insulation layer 4. R2 is a ratio of a latent heat amount of the heat storage layer within a temperature range from 15°C up to 50°C with respect to a latent heat amount within a temperature range from -10°C up to 60°C. R3=L5/L20 (2).SELECTED DRAWING: Figure 1
【課題】室外の気温の変動によらず、冷暖房設備により室内の温度を一定に保持させる際に、室内への流出入熱量を小さくし、冷暖房エネルギーを低減することが可能な屋根部材または天井部材を提供する。【解決手段】室外側断熱層３と室内側断熱層４との間に、蓄熱層２を有し、下式（３）で表されるＲが０．１０以下である屋根部材１または天井部材。Ｒ＝２（Ｒ１−０．５）２＋（Ｒ２−１）２＋（Ｒ３−０．５５）２（３）、Ｒ１=（Ｔｂ／Ｋｂ）／（Ｔａ／Ｋａ+Ｔｂ／Ｋｂ）（１）、Ｋａは室外側断熱層３の熱伝導率であり、Ｔａは室外側断熱層３厚みであり、Ｋｂは室内側断熱層４の熱伝導率であり、Ｔｂは室内側断熱層４の厚みである。Ｒ２は、蓄熱層の、−１０℃から６０℃の温度範囲内の潜熱量に対する、１５℃から５０℃の温度範囲内の潜熱量の比である。Ｒ３＝Ｌ５／Ｌ２０（２）【選択図】図１
ROOF MEMBER OR CEILING MEMBER, AND BUILDING
To provide a roof member or a ceiling member which can reduce a flow-in/out calorie to/from a room when constantly maintaining room temperature by cooling/heating equipment irrespective of a variation of an outdoor atmospheric temperature, and can reduce cooling/heating energy.SOLUTION: In a roof member 1 or a ceiling member, a heat storage layer 2 is arranged between an outdoor heat insulation layer 3 and an indoor heat insulation layer 4, and R expressed by the following formula (3) is 0.10 or smaller. R=2(R1-0.5)2+(R2-1)2+(R3-0.55)2 (3), and R1=(Tb/Kb)/(Ta/Ka+Tb/Kb) (1), where Ka is the heat conductivity of the outdoor heat insulation layer 3, Ta is a thickness of the outdoor heat insulation layer 3, Kb is the heat conductivity of the indoor heat insulation layer 4, and Tb is a thickness of the indoor heat insulation layer 4. R2 is a ratio of a latent heat amount of the heat storage layer within a temperature range from 15°C up to 50°C with respect to a latent heat amount within a temperature range from -10°C up to 60°C. R3=L5/L20 (2).SELECTED DRAWING: Figure 1
【課題】室外の気温の変動によらず、冷暖房設備により室内の温度を一定に保持させる際に、室内への流出入熱量を小さくし、冷暖房エネルギーを低減することが可能な屋根部材または天井部材を提供する。【解決手段】室外側断熱層３と室内側断熱層４との間に、蓄熱層２を有し、下式（３）で表されるＲが０．１０以下である屋根部材１または天井部材。Ｒ＝２（Ｒ１−０．５）２＋（Ｒ２−１）２＋（Ｒ３−０．５５）２（３）、Ｒ１=（Ｔｂ／Ｋｂ）／（Ｔａ／Ｋａ+Ｔｂ／Ｋｂ）（１）、Ｋａは室外側断熱層３の熱伝導率であり、Ｔａは室外側断熱層３厚みであり、Ｋｂは室内側断熱層４の熱伝導率であり、Ｔｂは室内側断熱層４の厚みである。Ｒ２は、蓄熱層の、−１０℃から６０℃の温度範囲内の潜熱量に対する、１５℃から５０℃の温度範囲内の潜熱量の比である。Ｒ３＝Ｌ５／Ｌ２０（２）【選択図】図１
ROOF MEMBER OR CEILING MEMBER, AND BUILDING
屋根部材または天井部材、及び建築物
HIROTA TOMOO (author) / MATSUI HIROICHI (author)
2020-07-27
Patent
Electronic Resource
Japanese
IPC:
E04B
Allgemeine Baukonstruktionen
,
GENERAL BUILDING CONSTRUCTIONS
/
B32B
LAYERED PRODUCTS, i.e. PRODUCTS BUILT-UP OF STRATA OF FLAT OR NON-FLAT, e.g. CELLULAR OR HONEYCOMB, FORM
,
Schichtkörper, d.h. aus Ebenen oder gewölbten Schichten, z.B. mit zell- oder wabenförmiger Form, aufgebaute Erzeugnisse
/
E04D
ROOF COVERINGS
,
Dacheindeckungen
/
E04F
FINISHING WORK ON BUILDINGS, e.g. STAIRS, FLOORS
,
Ausbau von Bauwerken, z.B. Treppen, Fußböden
CEILING BASE MEMBER, CEILING STRUCTURE, BUILDING, AND CONSTRUCTION METHOD OF BUILDING
| European Patent Office | 2023