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DISPLAY MEMBER FOR FLOOR SLAB CONSTRUCTION AND FLOOR SLAB CONSTRUCTION METHOD
To clearly determine a position where a reinforcement should be cut and accurately install a void at an accurate position when a floor slab having a through hole is constructed, and secure a predetermined covering depth between an inner peripheral surface of the through hole of the floor slab and the reinforcement.SOLUTION: An inner circle 21 and an outer circle 22 are formed on an upper surface 11 of a planar display member 10. The size of the inner circle 21 corresponds to the size of a through hole 2 of a floor slab 1. A radius difference Δr20 between the outer circle 22 and the inner circle 21 corresponds to a covering depth t1a between an inner peripheral surface of the through hole 2 and a reinforcement 3 in the floor slab 1. The display member 10 is arranged at a predetermined position of a form 4 defining a bottom surface of the floor slab 1. After the reinforcement 3 is arranged, the reinforcement 3 crossing the outer circle 22 is cut and removed right above the outer circle 22, and a void 6 is arranged on the inner circle 21 in planar projection view.SELECTED DRAWING: Figure 4
【課題】貫通穴を有する床スラブの施工に際して、鉄筋を切断すべき位置を明確に判断でき、かつボイドを正確な位置に設置でき、ひいては床スラブの貫通穴の内周面と鉄筋との間に所定のかぶり厚さを確保する。【解決手段】面状の表示部材10の上面11に内側円21及び外側円22を形成する。内側円21の大きさを床スラブ1の貫通穴2の大きさと対応させる。外側円22と内側円21との半径差Δr20を貫通穴2の内周面と床スラブ1内の鉄筋3とのかぶり厚さt1aと対応させる。表示部材10を、床スラブ1の底面を画成する型枠4の所定位置に配置する。鉄筋3を配筋した後、平面投影視において、外側円22と交差する鉄筋3を外側円22の直上において切断して撤去し、内側円21の上にボイド6を配置する。【選択図】図4
DISPLAY MEMBER FOR FLOOR SLAB CONSTRUCTION AND FLOOR SLAB CONSTRUCTION METHOD
To clearly determine a position where a reinforcement should be cut and accurately install a void at an accurate position when a floor slab having a through hole is constructed, and secure a predetermined covering depth between an inner peripheral surface of the through hole of the floor slab and the reinforcement.SOLUTION: An inner circle 21 and an outer circle 22 are formed on an upper surface 11 of a planar display member 10. The size of the inner circle 21 corresponds to the size of a through hole 2 of a floor slab 1. A radius difference Δr20 between the outer circle 22 and the inner circle 21 corresponds to a covering depth t1a between an inner peripheral surface of the through hole 2 and a reinforcement 3 in the floor slab 1. The display member 10 is arranged at a predetermined position of a form 4 defining a bottom surface of the floor slab 1. After the reinforcement 3 is arranged, the reinforcement 3 crossing the outer circle 22 is cut and removed right above the outer circle 22, and a void 6 is arranged on the inner circle 21 in planar projection view.SELECTED DRAWING: Figure 4
【課題】貫通穴を有する床スラブの施工に際して、鉄筋を切断すべき位置を明確に判断でき、かつボイドを正確な位置に設置でき、ひいては床スラブの貫通穴の内周面と鉄筋との間に所定のかぶり厚さを確保する。【解決手段】面状の表示部材10の上面11に内側円21及び外側円22を形成する。内側円21の大きさを床スラブ1の貫通穴2の大きさと対応させる。外側円22と内側円21との半径差Δr20を貫通穴2の内周面と床スラブ1内の鉄筋3とのかぶり厚さt1aと対応させる。表示部材10を、床スラブ1の底面を画成する型枠4の所定位置に配置する。鉄筋3を配筋した後、平面投影視において、外側円22と交差する鉄筋3を外側円22の直上において切断して撤去し、内側円21の上にボイド6を配置する。【選択図】図4
DISPLAY MEMBER FOR FLOOR SLAB CONSTRUCTION AND FLOOR SLAB CONSTRUCTION METHOD
床スラブ施工用表示部材及び床スラブ施工方法
NISHINO YOSHIKAZU (author) / AKASHI REI (author) / KOSAKA NAOYA (author) / TANIGUCHI HIROSHI (author) / SAKAGAMI NORIO (author)
2021-11-18
Patent
Electronic Resource
Japanese
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